4x^2-16=8x+4

Solution for 4x^2-16=8x+4 equation:

4x^2-16=8x+4

We move all terms to the left:

4x^2-16-(8x+4)=0

We get rid of parentheses

4x^2-8x-4-16=0

We add all the numbers together, and all the variables

4x^2-8x-20=0

a = 4; b = -8; c = -20;
Δ = b2-4ac
Δ = -82-4·4·(-20)
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8\sqrt{6}}{2*4}=\frac{8-8\sqrt{6}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8\sqrt{6}}{2*4}=\frac{8+8\sqrt{6}}{8}
$